Solve 3x2 = 27. a ±3 b ±9 c square root 3 d 3 times square root 3

Solve 3x2 = 27.

a
±3

b
±9

c
square root 3
d
3 times square root 3

Hello!

3x² = 27

3x²/3 = 27/3

x² = 9

√x² = ±√9

x = ±3

The solution of the equation is :

↬ choice A

Solution:

Our equation is: [tex]\sf{3x^2=27}[/tex].

To solve it, we should isolate the x. So I begin by dividing each side by 3:

[tex]\sf{3x^2=27}[/tex]

[tex]\sf{x^2=9}[/tex]

Now, to get rid of the square on top of the x, I take the square-root of each side; the square-root and the square will cancel out on the left.

Keep in mind that once you take the square root of a number, you end up with TWO solutions.

So the result is:

[tex]\sf{x=3, x=-3}[/tex], which can be rewritten as x = ± 3

Hence, x = ± 3

0 Response to "Solve 3x2 = 27. a ±3 b ±9 c square root 3 d 3 times square root 3"

Post a Comment

Iklan Atas Artikel

Iklan Tengah Artikel 1

Iklan Tengah Artikel 2

Iklan Bawah Artikel